A) 165 Hz
B) 330 Hz
C) 496 Hz
D) 660 Hz
Correct Answer: B
Solution :
Path difference between the wave reaching at D \[\Delta x={{L}_{2}}P-{{L}_{1}}P\]\[=\sqrt{{{40}^{2}}+{{9}^{2}}}-40\]\[=41-40\]= 1m For maximum \[\Delta x=(2n)\frac{\lambda }{2}\] For first maximum (n = 1) Þ\[1=2(1)\frac{\lambda }{2}\]Þ \[\lambda =1m\] Þ \[n=\frac{v}{\lambda }=330Hz\].
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