A) \[C{{H}_{3}}-C{{H}_{2}}-\underset{Br}{\mathop{\underset{|\,\,\,\,\,}{\mathop{C{{H}_{2}}}}\,}}\,\]
B) \[C{{H}_{3}}-\underset{Br}{\mathop{\underset{|\,\,\,}{\mathop{CH}}\,}}\,--\underset{C{{H}_{3}}}{\mathop{\underset{|\,\,\,\,\,\,\,}{\mathop{CH-}}\,}}\,C{{H}_{3}}\]
C) \[C{{H}_{3}}-C{{H}_{2}}-\underset{Br}{\mathop{\underset{|\,\,\,}{\mathop{CH}}\,}}\,-C{{H}_{3}}\]
D) \[C{{H}_{3}}-\underset{Br\,}{\mathop{\underset{|\,\,\,\,}{\mathop{\overset{C{{H}_{3}}}{\mathop{\overset{|\,\,\,\,}{\mathop{C-}}\,}}\,}}\,}}\,C{{H}_{2}}-C{{H}_{2}}-C{{H}_{3}}\]
Correct Answer: B
Solution :
\[C{{H}_{3}}-\underset{Br}{\overset{H\,\,\,}{\mathop{\underset{|\,\,\,\,}{\overset{|\,\,\,\,\,}{\mathop{{{C}^{*}}}}}\,}}}\,-\underset{C{{H}_{3}}}{\mathop{\underset{|\,\,\,\,\,\,\,\,\,}{\mathop{CH\,\,}}\,}}\,-C{{H}_{3}}\] and \[C{{H}_{3}}-C{{H}_{2}}-\underset{Br}{\overset{H\,\,}{\mathop{\underset{|\,\,\,\,\,}{\overset{|\,\,\,\,\,}{\mathop{{{C}^{*}}}}}\,}}}\,-C{{H}_{3}}\]
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