A) \[{{\left( \frac{{{R}_{6}}}{{{R}_{2}}} \right)}^{2}}I\]
B) \[{{\left( \frac{{{R}_{7}}}{{{R}_{2}}} \right)}^{2}}I\]
C) \[{{\left( \frac{{{R}_{8}}}{{{R}_{2}}} \right)}^{2}}I\]
D) \[{{\left( \frac{{{R}_{9}}}{{{R}_{2}}} \right)}^{2}}I\]
Correct Answer: D
Solution :
\[I=\frac{R_{2}^{2}}{4}\]given \[{{n}_{1}}{{b}_{1}}={{n}_{2}}{{b}_{2}}\] Þ \[1\times 200={{n}_{2}}\times 25\] \[\therefore {{n}_{2}}=8\ HPZ\] \[\therefore I={{\left( \frac{{{R}_{9}}}{2} \right)}^{2}}\] \[={{\left( \frac{{{R}_{9}}}{{{R}_{8}}}\times \frac{{{R}_{8}}}{{{R}_{7}}}\times \frac{{{R}_{7}}}{{{R}_{6}}}\times \frac{{{R}_{6}}}{{{R}_{5}}}\times \frac{{{R}_{5}}}{{{R}_{4}}}\times \frac{{{R}_{4}}}{{{R}_{3}}}\times \frac{{{R}_{3}}}{{{R}_{2}}}\times \frac{{{R}_{2}}}{{{R}_{2}}} \right)}^{2}}\] \[={{\left( \frac{{{R}_{9}}}{{{R}_{2}}} \right)}^{2}}I\]
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