A) \[3-i\sqrt{6},\pm \sqrt{\frac{3}{2}}\]
B) \[3-i\sqrt{6},\pm \frac{3}{\sqrt{2}}\]
C) \[3-i\sqrt{6},\pm \frac{\sqrt{3}}{2}\]
D) None of these
Correct Answer: C
Solution :
\[{{x}^{2}}-6x+15=0\]is quadratic corresponding to roots \[3\pm i\sqrt{6}\] and dividing the given equation by this, we get \[4{{x}^{2}}-3=0\]Þ \[x=\pm \frac{\sqrt{3}}{2}\].
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