• # question_answer 34) The roots of the equation$4{{x}^{4}}-24{{x}^{3}}+57{{x}^{2}}+18x-45=0$, If one of them is$3+i\sqrt{6}$, are A) $3-i\sqrt{6},\pm \sqrt{\frac{3}{2}}$ B) $3-i\sqrt{6},\pm \frac{3}{\sqrt{2}}$ C) $3-i\sqrt{6},\pm \frac{\sqrt{3}}{2}$ D) None of these

${{x}^{2}}-6x+15=0$is quadratic corresponding to roots $3\pm i\sqrt{6}$ and dividing the given equation by this, we get  $4{{x}^{2}}-3=0$Þ $x=\pm \frac{\sqrt{3}}{2}$.