A) \[{{\overset{+}{\mathop{C}}\,}_{2}}{{H}_{5}}\]
B) \[{{(C{{H}_{3}})}_{3}}\overset{+}{\mathop{C}}\,\]
C) \[{{({{C}_{6}}{{H}_{5}})}_{3}}\overset{+}{\mathop{C}}\,\]
D) \[{{C}_{6}}{{H}_{5}}\overset{+}{\mathop{C}}\,{{H}_{2}}\]
Correct Answer: C
Solution :
In the triphenyl methyl carbonium ion the p electrons of all the three benzene rings are delocalised with the vacant p-orbital of central carbon atom. So, it is resonance stabilised. It is the most stable of all the carbonium ions given The ion \[C{{H}_{3}}-\underset{C{{H}_{3}}}{\overset{C{{H}_{3}}}{\mathop{\underset{|\ \ }{\overset{|\ \ }{\mathop{{{C}^{+}}}}}\,\ \ }}}\,\] is stabilised by hyperconjugation, a second order resonance.
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