A) \[B{{F}_{3}}\]
B) \[N{{H}_{3}}\]
C) \[BeC{{l}_{2}}\]
D) \[{{H}_{2}}O\]
Correct Answer: B
Solution :
\[\overset{\cdot \,\,\cdot }{\mathop{N}}\,{{H}_{3}}\] presence of lone pair of electrons.
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