JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Critical Thinking

  • question_answer
    What is \[[{{H}^{+}}]\] of a solution that is \[0.01\,M\] in \[HCN\]and \[0.02\,M\] in \[NaCN\] \[({{K}_{a}}\]for \[HCN=6.2\times {{10}^{-10}})\]                                              [MP PMT 2000]

    A)                 \[3.1\times {{10}^{10}}\]             

    B)                 \[6.2\times {{10}^{5}}\]

    C)                 \[6.2\times {{10}^{-10}}\]            

    D)                 \[3.1\times {{10}^{-10}}\]

    Correct Answer: D

    Solution :

               \[{{K}_{a}}=\frac{[{{H}^{+}}]\,\,[C{{N}^{-}}]}{[HC{{N}^{-}}]}\]                    \[6.2\times {{10}^{-10}}=\frac{[{{H}^{+}}]\,\,[0.02]}{[0.01]}\]                                 \[[{{H}^{+}}]=\frac{6.2\times {{10}^{-10}}\times 0.01}{0.02}=3.1\times {{10}^{-10}}\]


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