A) 3
B) 6
C) 7
D) 10
Correct Answer: C
Solution :
\[{{C}_{4}}{{H}_{10}}O\] have 7 isomers out of which 4 are alcohols and 3 are ethers. 1. \[\underset{n-\text{butyl}\,\text{alcohol}}{\mathop{C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}-C{{H}_{2}}-OH}}\,\], 2. \[\underset{\text{Sec}-\text{butyl}\,\text{alcohol}}{\mathop{C{{H}_{3}}-C{{H}_{2}}-\underset{OH}{\mathop{\underset{|\,\,\,\,\,}{\mathop{CH}}\,}}\,-C{{H}_{3}}}}\,\] 3. \[\underset{\text{Isobutyl}\,\text{alcohol}}{\mathop{C{{H}_{3}}-\underset{C{{H}_{3}}}{\mathop{\underset{|\,\,\,\,\,\,\,}{\mathop{CH}}\,}}\,-C{{H}_{2}}-OH}}\,\] 4. \[\underset{\text{Ter}-\text{buty}-\text{alcohol}}{\mathop{C{{H}_{3}}-\overset{C{{H}_{3}}}{\mathop{\underset{\underset{OH}{\mathop{|\,\,\,\,\,\,}}\,}{\overset{|\,\,\,\,\,\,}{\mathop{C\,\,-\,}}}\,}}\,C{{H}_{3}}}}\,\] 5. \[\underset{\text{Diethyl}\,\text{ether}}{\mathop{C{{H}_{3}}-C{{H}_{2}}-O-C{{H}_{2}}-C{{H}_{3}}}}\,\] 6. \[\underset{\text{Methyl}\,\text{propyl}\,\text{ether}}{\mathop{C{{H}_{3}}-O-C{{H}_{2}}-C{{H}_{2}}-C{{H}_{3}}}}\,\] 7. \[\underset{\text{Methyl}\,\text{isopropyl}\,\text{ether}}{\mathop{C{{H}_{3}}-O-CH<_{C{{H}_{3}}}^{C{{H}_{3}}}}}\,\]
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