question_answer

In the circuit shown in figure the maximum output voltage V0 is

A)            0 V                                            

B)            5 V

C)            10 V                                         

D)            \[\frac{5}{\sqrt{2}}V\]

Correct Answer: B

Solution :

                   For the positive half cycle of input the resulting network is shown below Þ (V0)max = \[\frac{1}{2}{{({{V}_{i}})}_{\max }}=\frac{1}{2}\times 10=5\,V.\]