A) 0.2 V
B) 0.4 V
C) 0.6 V
D) 0.8 V
Correct Answer: B
Solution :
Consider the case when Ge and Si diodes are connected as show in the given figure. Equivalent voltage drop across the combination Ge and Si diode = 0.3 V Þ Current \[i=\frac{12-0.3}{5\,k\Omega }=2.34\,mA\] \ Output voltage V0 = Ri = 5 kW ´ 2.34 mA = 11.7 V Now consider the case when diode connection are reversed. In this case voltage drop across the diode's combination = 0.7 V Þ Current \[i=\frac{12-0.7}{5\,k\Omega }=2.26\,mA\] \ \[{{V}_{0}}=iR=2.26\,mA\times 5\,k\Omega =11.3\,V\] Hence charge in the value of V0 = 11.7 ?11.3 = 0.4 V
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