JEE Main & Advanced Mathematics Binomial Theorem and Mathematical Induction Question Bank Critical Thinking

  • question_answer
    \[\left( \begin{matrix}    n  \\    0  \\ \end{matrix} \right)+2\,\left( \begin{matrix}    n  \\    1  \\ \end{matrix} \right)+{{2}^{2}}\left( \begin{matrix}    n  \\    2  \\ \end{matrix} \right)+.....+{{2}^{n}}\left( \begin{matrix}    n  \\    n  \\ \end{matrix} \right)\] is equal to   [AMU 2000]

    A) \[{{2}^{n}}\]

    B) 0

    C) \[{{3}^{n}}\]

    D) None of these

    Correct Answer: C

    Solution :

    \[{{(1+x)}^{n}}={}^{n}{{C}_{0}}+x.{}^{n}{{C}_{1}}+{{x}^{2}}.{}^{n}{{C}_{2}}+....+{{x}^{n}}.{}^{n}{{C}_{n}}\] Put x = 2   Þ \[{{3}^{n}}={}^{n}{{C}_{0}}+2.{}^{n}{{C}_{1}}+{{2}^{2}}.{}^{n}{{C}_{2}}+{{2}^{3}}.{}^{n}{{C}_{3}}+....+{{2}^{n}}{{.}^{n}}{{C}_{n}}\].


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