A) Bond order three and isoelectronic
B) Bond order three and weak field ligands
C) Bond order two and p-acceptors
D) Isoelectronic and weak field ligands
Correct Answer: A
Solution :
Each of the species has 14 electron so isoelectronic and shows bond order 3. B.O.\[=\frac{1}{2}[{{N}_{b}}-{{N}_{a}}]\]\[=\frac{1}{2}[10-4]=\frac{6}{2}=3\].You need to login to perform this action.
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