JEE Main & Advanced Chemistry GOC Question Bank Critical Thinking

  • question_answer The following reaction is described as [CBSE PMT 1997] \[\begin{matrix}    C{{H}_{3}}{{(C{{H}_{2}})}_{5}}  \\    {}  \\    {{H}_{3}}C  \\ \end{matrix}>\underset{H}{\mathop{\underset{|}{\mathop{C}}\,}}\,-Br\xrightarrow{OH}HO-\underset{H}{\mathop{\underset{|}{\mathop{C}}\,}}\,<\begin{matrix}    {{(C{{H}_{2}})}_{5}}C{{H}_{3}}  \\    {}  \\    C{{H}_{3}}\,\,\,\,\,\,\,\,\,\,\,  \\ \end{matrix}\]

    A) \[S{{E}^{2}}\]

    B) \[S{{N}^{1}}\]

    C) \[S{{N}^{2}}\]

    D) \[S{{N}^{0}}\]

    Correct Answer: C

    Solution :

    In this reaction inversion of configuration takes place this is called optical inversion. It is an example of \[S{{N}^{2}}\] reaction (Bimolecular Nucleophillic Substitution).


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