A) From \[n=1\] to \[n=2\]
B) From \[n=2\] to \[n=3\]
C) From \[n=\infty \] to \[n=1\]
D) From \[n=3\] to \[n=5\]
Correct Answer: A
Solution :
\[E\propto \left[ \frac{1}{n_{2}^{2}}-\frac{1}{n_{1}^{2}} \right]\]
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