A) 310 \[c{{m}^{3}}\]
B) 290 \[c{{m}^{3}}\]
C) 10 \[c{{m}^{3}}\]
D) 37 \[c{{m}^{3}}\]
Correct Answer: C
Solution :
\[\frac{{{V}_{2}}}{{{V}_{1}}}=\frac{{{T}_{2}}}{{{T}_{1}}}\] \[\because {{V}_{2}}=\frac{{{T}_{2}}}{{{T}_{1}}}{{V}_{1}}=\frac{{{310}^{o}}K}{{{300}^{o}}K}\times 300c{{m}^{3}}=310c{{m}^{3}}\]
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