A) \[C{{H}_{3}}C{{H}_{2}}Cl\]
B) \[\begin{matrix} C{{H}_{3}} \\ C{{H}_{3}} \\ \end{matrix}>CH-Cl\]
C) \[C{{H}_{3}}-\underset{C{{H}_{3}}\ }{\overset{C{{H}_{3}}\ }{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,-Cl}}}\,\]
D) \[C{{H}_{3}}-\underset{C{{H}_{3}}}{\mathop{\underset{\underset{|}{\mathop{C}}\,{{H}_{2}}}{\mathop{\underset{|}{\mathop{C}}\,H\ }}\,}}\,-Cl\]
Correct Answer: C
Solution :
\[S{{N}^{1}}\] mechanism proceeds through carbocation intermediate. \[C{{H}_{3}}-\underset{C{{H}_{3}}\ \,}{\overset{C{{H}_{3}}\ \ }{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,-Cl}}}\,\]
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