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JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Critical Thinking

  • question_answer
    Dissociation constant of a weak acid is \[1\times {{10}^{-4}}\]. Equilibrium constant of its reaction with strong base is      [UPSEAT 2003]

    A)                 \[1\times {{10}^{-4}}\]  

    B)                 \[1\times {{10}^{10}}\]

    C)                 \[1\times {{10}^{-10}}\]               

    D)                 \[1\times {{10}^{14}}\]

    Correct Answer: B

    Solution :

                    \[{{K}_{H}}=\frac{{{K}_{a}}}{{{K}_{w}}}=\frac{{{10}^{-4}}}{{{10}^{-14}}}=\frac{1}{{{10}^{-10}}}={{10}^{10}}\].


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