JEE Main & Advanced Physics Wave Optics / तरंग प्रकाशिकी Question Bank Critical Thinking

  • question_answer
    In a two slit experiment with monochromatic light fringes are obtained on a screen placed at some distance from the sits. If the screen is moved by \[5\times {{10}^{-2}}m\] towards the slits, the change in fringe width is\[3\times {{10}^{-5}}m\]. If separation between the slits is \[{{10}^{-3}}m\], the wavelength of light used is [Roorkee 1992]

    A) \[6000\,\,{AA}\]

    B) \[5000\,\,{AA}\]

    C) \[3000\,\,{AA}\]               

    D) \[4500\,\,{AA}\]

    Correct Answer: A

    Solution :

    \[\beta =\frac{\lambda D}{d}\] Þ b µ D Þ \[\frac{{{\beta }_{1}}}{{{\beta }_{2}}}=\frac{{{D}_{1}}}{{{D}_{2}}}\] Þ \[\frac{{{\beta }_{1}}-{{\beta }_{2}}}{{{\beta }_{2}}}=\frac{{{D}_{1}}-{{D}_{2}}}{{{D}_{2}}}\]Þ \[\frac{\Delta \beta }{\Delta D}=\frac{{{\beta }_{2}}}{{{D}_{2}}}=\frac{{{\lambda }_{2}}}{{{d}_{2}}}\] \[={{\lambda }_{2}}=\frac{3\times {{10}^{-5}}}{5\times {{10}^{-2}}}\times {{10}^{-3}}=6\times {{10}^{-7}}m=6000{AA}\]


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