A) \[T\frac{\rho -1}{\rho }\]
B) \[T\frac{\rho }{\rho -1}\]
C) \[T\sqrt{\frac{\rho -1}{\rho }}\]
D) \[T\sqrt{\frac{\rho }{\rho -1}}\]
Correct Answer: D
Solution :
When the bob is immersed in water its effective weight = \[\left( mg-\frac{m}{\rho }g \right)=mg\,\left( \frac{\rho -1}{\rho } \right)\] \[\therefore {{g}_{eff}}=g\,\left( \frac{\rho -1}{\rho } \right)\] \[\frac{T'}{T}=\sqrt{\frac{g}{{{g}_{eff}}}}\]\[{{T}_{1}}=2\pi \sqrt{\frac{m}{K}}\]
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