A) \[2N{{H}_{3}}+{{H}_{2}}S{{O}_{4}}\]⇄ \[2NH_{4}^{+}+SO_{4}^{2-}\]
B) \[N{{H}_{3}}+C{{H}_{3}}COOH\]⇄ \[NH_{4}^{+}+C{{H}_{3}}CO{{O}^{-}}\]
C) \[{{H}_{2}}O+C{{H}_{3}}COOH\]⇄ \[{{H}_{3}}{{O}^{+}}+C{{H}_{3}}CO{{O}^{-}}\]
D) \[{{[Cu{{({{H}_{2}}O)}_{4}}]}^{2+}}+4N{{H}_{3}}\]⇄ \[{{[Cu{{(N{{H}_{3}})}_{4}}]}^{2+}}+4{{H}_{2}}O\]
Correct Answer: D
Solution :
It involves gain and loss of electron pair (Lewis concept).
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