A) \[p{{H}_{1}}>p{{H}_{2}}=p{{H}_{3}}>p{{H}_{4}}\]
B) \[p{{H}_{1}}<p{{H}_{2}}<p{{H}_{3}}<p{{H}_{4}}\]
C) \[p{{H}_{1}}<p{{H}_{2}}<p{{H}_{3}}=p{{H}_{4}}\]
D) \[p{{H}_{1}}>p{{H}_{2}}>p{{H}_{3}}>p{{H}_{4}}\]
Correct Answer: D
Solution :
Order of acidic strength is \[{{H}_{2}}Te>{{H}_{2}}Se>{{H}_{2}}S>{{H}_{2}}O\] \[N{{a}_{2}}O\] is a salt of \[NaOH+{{H}_{2}}O\]and \[{{H}_{2}}O\]is least acidic among given acids hence pH in this case will be maximum.
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