JEE Main & Advanced Chemistry Structure of Atom Question Bank Critical Thinking

  • question_answer The ionization energy of hydrogen atom is \[-13.6\,eV.\] The energy required to excite the electron in a hydrogen atom from the ground state to the first excited state is (Avogadro?s constant = 6.022 × 1023)   [BHU 1999]

    A)                 \[1.69\times {{10}^{-20}}J\]        

    B)                 \[1.69\times {{10}^{-23}}J\]

    C)                 \[1.69\times {{10}^{23}}J\]         

    D)                 \[1.69\times {{10}^{25}}J\]

    Correct Answer: B

    Solution :

               \[E=\frac{-13.6}{{{n}^{2}}}=\frac{-13.6}{4}=-3.4\,eV\] We know that energy required for excitation \[\Delta E={{E}_{2}}-{{E}_{1}}\] \[=-3.4-(-13.6)=10.2\,eV\]                 Therefore energy required for excitation of electron per atom \[=\frac{10.2}{6.02\times {{10}^{23}}}=1.69\times {{10}^{-23}}J\]

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