A) \[4\,Cr-O\]bonds are equivalent
B) \[6\,Cr-O\]bonds are equivalent
C) All \[Cr-O\] bonds are equivalent
D) All \[Cr-O\] bonds are non-equivalent
Correct Answer: B
Solution :
Dichromate dianion has following structure \[{{\left[ O\leftarrow \underset{O}{\overset{O}{\mathop{\underset{\downarrow }{\overset{\uparrow }{\mathop{Cr}}}\,}}}\,-O-\underset{O}{\overset{O}{\mathop{\underset{\downarrow }{\overset{\uparrow }{\mathop{Cr}}}\,}}}\,\to O \right]}^{2-}}\] 6, \[Cr-O\] bonds are equivalent.
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