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JEE Main & Advanced Physics Wave Optics / तरंग प्रकाशिकी Question Bank Critical Thinking

  • question_answer
    The time period of rotation of the sun is 25 days and its radius is\[7\times {{10}^{8}}m\]. The Doppler shift for the light of wavelength\[6000\,\,{AA}\]emitted from the surface of the sun will be                                                              [MP PMT 1994]

    A) \[0.04\,\,{AA}\]                

    B) \[0.40\,\,{AA}\]

    C) \[4.00\,\,{AA}\]

    D) \[40.0\,\,{AA}\]

    Correct Answer: A

    Solution :

    \[\Delta \lambda =\lambda \frac{v}{c}\]and \[v=r\omega \] \[v=7\times {{10}^{8}}\times \frac{2\pi }{25\times 24\times 3600},\ c=3\times {{10}^{8}}m/s\] \[\therefore \Delta \lambda =0.04{AA}\]


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