• # question_answer The coefficient of $x$ in the equation ${{x}^{2}}+px+q=0$was taken as 17 in place of 13, its roots were found to be -2 and -15, The roots of the original equation are      [IIT 1977, 79] A)  3, 10 B) - 3, - 10 C) - 5, - 18 D)  None of these

Let the equation (in correctly written form) be${{x}^{2}}+17x+q=0$. Roots are - 2, - 15. So 30=q, so correct equation is${{x}^{2}}+13x+30=0$. Hence roots are - 3, - 10.