JEE Main & Advanced Mathematics Quadratic Equations Question Bank Critical Thinking

  • question_answer 11) The coefficient of \[x\] in the equation \[{{x}^{2}}+px+q=0\]was taken as 17 in place of 13, its roots were found to be -2 and -15, The roots of the original equation are      [IIT 1977, 79]

    A)  3, 10

    B) - 3, - 10

    C) - 5, - 18

    D)  None of these

    Correct Answer: B

    Solution :

    Let the equation (in correctly written form) be\[{{x}^{2}}+17x+q=0\]. Roots are - 2, - 15. So 30=q, so correct equation is\[{{x}^{2}}+13x+30=0\]. Hence roots are - 3, - 10.

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