JEE Main & Advanced Chemistry Structure of Atom Question Bank Critical Thinking

  • question_answer The total number of valence electrons in \[4.2\,gm\] of \[N_{3}^{-}\]  ion is (\[{{N}_{A}}\] is the Avogadro's number)     [CBSE PMT 1994]

    A)                 \[1.6{{N}_{A}}\]               

    B)                 \[3.2{{N}_{A}}\]

    C)                 \[2.1{{N}_{A}}\]               

    D)                 \[4.2{{N}_{A}}\] 

    Correct Answer: A

    Solution :

                    42g of \[N_{3}^{-}\] ions have \[16\,{{N}_{A}}\] valence electrons 4.2g  of  \[N_{3}^{-}\] ion have \[=\frac{16\,{{N}_{A}}}{42}\times 4.2=1.6\,{{N}_{A}}\].


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