A) \[1.6{{N}_{A}}\]
B) \[3.2{{N}_{A}}\]
C) \[2.1{{N}_{A}}\]
D) \[4.2{{N}_{A}}\]
Correct Answer: A
Solution :
42g of \[N_{3}^{-}\] ions have \[16\,{{N}_{A}}\] valence electrons 4.2g of \[N_{3}^{-}\] ion have \[=\frac{16\,{{N}_{A}}}{42}\times 4.2=1.6\,{{N}_{A}}\].
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