JEE Main & Advanced Physics Semiconducting Devices Question Bank Critical Thinking

  • question_answer
    For a transistor amplifier in common emitter configuration for load impedance of 1 kW (hfe = 50 and hoe = 25 mA/V) the current gain is                                                                  [AIEEE 2004]

    A)            ? 5.2                                        

    B)            ? 15.7

    C)            ? 24.8                                      

    D)            ? 48.78

    Correct Answer: D

    Solution :

                       In common emitter configuration current gain            \[{{A}_{i}}=\frac{-{{h}_{fe}}}{1+{{h}_{oe}}{{R}_{L}}}=\frac{-50}{1+25\times {{10}^{-6}}\times {{10}^{3}}}\]= ? 48.78.


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