A) \[\frac{4}{3}\]
B) \[\frac{3}{4}\]
C) \[\frac{1}{2}\]
D) 2
Correct Answer: B
Solution :
Since \[{{\cos }^{6}}\alpha +{{\sin }^{6}}\alpha +K{{\sin }^{2}}2\alpha =1\] using formula \[{{a}^{3}}+{{b}^{3}}={{(a+b)}^{3}}-3ab(a+b)\] and on solving, we get the required result i.e. \[K=\frac{3}{4}\].
You need to login to perform this action.
You will be redirected in
3 sec
