A) 1
B) 8
C) 4
D) 2
Correct Answer: D
Solution :
Frequency of vibration in tight string \[n=\frac{p}{2l}\sqrt{\frac{T}{m}}\Rightarrow n\propto \sqrt{T}\]Þ\[\frac{\Delta n}{n}=\frac{\Delta T}{2T}=\frac{1}{2}\times (4%)=2%\] Þ Number of beats = \[\Delta n=\frac{2}{100}\times n=\frac{2}{100}\times 100=2\]
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