JEE Main & Advanced Chemistry Chemical Bonding and Molecular Structure Question Bank Critical Thinking

  • question_answer The values of electronegativity of atoms A and B are 1.20 and 4.0 respectively. The percentage of ionic character of    A ? B bond is                                                 [MP PET 2003]

    A)                 50 %      

    B)                 43 %

    C)                 55.3 %  

    D)                 72.24%

    Correct Answer: D

    Solution :

               We know that ionic characters         \[=16\,[{{E}_{A}}-{{E}_{B}}]+3.5\times {{[{{E}_{A}}-{{E}_{B}}]}^{2}}\]                                 or ionic characters = 72.24%


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