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JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Critical Thinking

  • question_answer
    If dissociation for reaction, \[PC{{l}_{5}}\]⇌ \[PC{{l}_{3}}+C{{l}_{2}}\]Is 20% at 1 atm. pressure. Calculate \[{{K}_{c}}\]                                                                                                                             [Kerala (Med.) 2003]

    A)                 0.04       

    B)                         0.05

    C)                 0.07       

    D)                 0.06

    Correct Answer: B

    Solution :

               \[{{K}_{c}}=\frac{[PC{{l}_{3}}][C{{l}_{2}}]}{[PC{{l}_{5}}]}=\frac{\left[ \frac{20}{100} \right]\times \left[ \frac{20}{100} \right]}{\left[ \frac{80}{100} \right]}\]                                 \[=\frac{0.2\times 0.2}{0.8}=\frac{0.04}{0.8}=0.05\]


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