• # question_answer In equations $3x-y\ge 3$ and $4x-y>4$ [MP PET 2001] A) Have solution for positive x and y            B) Have no solution for positive x and yC) Have solution for all xD) Have solution for all y

• From $3x-y\ge 3,\frac{x}{1}+\frac{y}{-3}=1$
• From $4x-y>4,\,\frac{x}{1}+\frac{y}{-4}=1$