A) \[\frac{2}{3}\]
B) \[\frac{5}{3}\]
C) \[\frac{4}{3}\]
D) None of these
Correct Answer: B
Solution :
Accordingly, \[{{(\sqrt{x})}^{10-r}}{{\left( \frac{1}{{{x}^{2}}} \right)}^{r}}={{x}^{0}}\Rightarrow r=2\] Hence the term is \[^{10}{{C}_{2}}{{\left( \frac{1}{\sqrt{3}} \right)}^{8}}.\,\,\,{{(\sqrt{3})}^{2}}=\frac{5}{3}\].
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