A) \[VC{{l}_{3}}\]
B) \[ScC{{l}_{3}}\]
C) \[TiC{{l}_{3}}\]
D) \[FeC{{l}_{3}}\]
Correct Answer: B
Solution :
\[ScC{{l}_{3}}\,\to \,S{{c}^{+3}}+3C{{l}^{-}}\]
No unpaired electron so will show diamagnetic character and will be repelled, so will weigh less.
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