A) \[\frac{\pi }{4}\]
B) \[\frac{\pi }{2}\]
C) \[\pi \]
D) \[2\pi \]
Correct Answer: A
Solution :
The given equation may be written as \[\frac{2}{\cos 2\alpha }=\frac{\sin \beta }{\cos \beta }+\frac{\cos \beta }{\sin \beta }=\frac{{{\sin }^{2}}\beta +{{\cos }^{2}}\beta }{\cos \beta \sin \beta }\]\[=\frac{1}{\cos \beta .\sin \beta }\] Þ \[\cos 2\alpha =\sin 2\beta \] Þ \[\cos 2\alpha \]= \[\cos \,\left( \frac{\pi }{2}-2\beta \right)\]Þ \[2\alpha =\frac{\pi }{2}-2\beta \] Þ Þ .You need to login to perform this action.
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