A) 0.01, 0.01
B) 0.02, 0.01
C) 0.01, 0.02
D) 0.02, 0.02
Correct Answer: A
Solution :
\[\underset{0.02\,\text{mole}}{\mathop{[Co\,{{(N{{H}_{3}})}_{5}}S{{O}_{4}}]\,Br}}\,+AgN{{O}_{3}}\to \]\[\underset{0.02\,\text{mole }(y)}{\mathop{[Co\,{{(N{{H}_{3}})}_{5}}.\,S{{O}_{4}}]\,N{{O}_{3}}}}\,+AgBr\] \[\underset{0.02\,\text{mole}}{\mathop{[Co\,{{(N{{H}_{3}})}_{5}}B{{r}_{2}}]S{{O}_{4}}}}\,+BaC{{l}_{2}}\to \]\[\underset{0.02\,\text{mole}\,(z)}{\mathop{[Co\,{{(N{{H}_{3}})}_{5}}Br]\,C{{l}_{2}}}}\,+BaS{{O}_{4}}\] On using one lit. Solution, we will get 0.01 mole y and 0.01 mole z.You need to login to perform this action.
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