A) 1.34 ml
B) 1.44 ml
C) 1.60 ml
D) 2.42 ml
Correct Answer: A
Solution :
20 ml of \[0.3N\] \[N{{a}_{2}}{{S}_{2}}{{O}_{3}}\] \[=20ml\] of \[0.3N\,{{I}_{2}}\] Solution \[=20\,ml\] of \[0.3N\,{{H}_{2}}{{O}_{2}}\] solution \[\equiv 25\,ml\] of \[0.08N\,{{H}_{2}}{{O}_{2}}\] solution Mass of \[{{H}_{2}}{{O}_{2}}\] \[100ml\] solution =\[\frac{0.08\times 17\times 100}{1000}\] \[=0.136\,gm\] % = 0.136 \[68\,gm\,\,{{H}_{2}}{{O}_{2}}\] evolve oxygen at NTP \[=22400\,ml\] \[0.00136\,gm\,{{H}_{2}}{{O}_{2}}\] evolve oxygen at NTP \[=\frac{22400}{68}\times 0.00136=0.448\] For \[0.1N\], the solution is of 0.448 volume. \[\therefore \] \[3N\], volume \[=0.448\times 3=1.344\,ml\].
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