A) \[\frac{\pi }{2}\]
B) \[\frac{\pi }{3}\]
C) \[\frac{\pi }{4}\]
D) \[\frac{\pi }{6}\]
Correct Answer: B
Solution :
\[(a+b+c)(a+b-c)=3ab\] Þ \[\frac{{{a}^{2}}+{{b}^{2}}-{{c}^{2}}}{2ab}=\frac{1}{2}\,\,\Rightarrow \cos C=\cos \frac{\pi }{3}\Rightarrow \angle C=\pi /3\]
You need to login to perform this action.
You will be redirected in
3 sec
