A) \[s\]
B) \[\frac{s}{abc}\]
C) \[\frac{{{s}^{2}}}{abc}\]
D) \[\frac{{{s}^{3}}}{abc}\]
Correct Answer: C
Solution :
\[\frac{1}{a}{{\cos }^{2}}\frac{A}{2}+\frac{1}{b}{{\cos }^{2}}\frac{B}{2}+\frac{1}{c}{{\cos }^{2}}\frac{C}{2}\] = \[\sum \frac{s(s-a)}{abc}=\frac{s(s-a+s-b+s-c)}{abc}=\frac{{{s}^{2}}}{abc}\].
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