A) \[{{C}_{4}}{{H}_{8}}{{O}_{2}}\]
B) \[{{C}_{2}}{{H}_{5}}COOH\]
C) \[C{{H}_{3}}COOH\]
D) \[C{{H}_{2}}=CH-COOH\]
Correct Answer: B
Solution :
\[\underset{\text{Ethylene}}{\mathop{{{C}_{2}}{{H}_{4}}}}\,+CO+{{H}_{2}}O\xrightarrow{\text{Ligh temp}\text{.}}\underset{\text{Propionic acid}}{\mathop{{{C}_{2}}{{H}_{5}}-COOH}}\,\]
You need to login to perform this action.
You will be redirected in
3 sec
