A) \[C{{H}_{2}}=CHBr\]
B) \[C{{H}_{3}}COC{{H}_{2}}C{{H}_{2}}Br\]
C) \[C{{H}_{3}}C{{H}_{2}}Br\]
D) \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}Br\]
Correct Answer: D
Solution :
The polarity between C-X bond increase by increasing the +I effect which increase by increasing the alkyl group by which X of C-X easily eliminate. In \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}Br\] the polarity is maximum due to 3 alkyl group while in rest polarity decrease due to the presence of double bond, presence of -CO group (-I) and less no. of alkyl group. \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}Br+KOH\xrightarrow{\text{alc}\text{.}}\]\[C{{H}_{3}}CH=C{{H}_{2}}+KBr+{{H}_{2}}O\]
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