A) Two free ions
B) Two-carbanium ion
C) Two carbanion
D) A cation and an anion
Correct Answer: D
Solution :
\[R-C{{H}_{2}}-Cl\xrightarrow{\text{Heterolytic bond fission}}\underset{\text{cation}}{\mathop{RCH_{2}^{\oplus }}}\,+\underset{\text{anion}}{\mathop{C{{l}^{}}}}\,\] Cl is more electronegative than C by which it form anion and hydrocarbon form cation.
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