JEE Main & Advanced Mathematics Inverse Trigonometric Functions Question Bank Critical Thinking

  • question_answer
    If \[{{\sin }^{-1}}x=\frac{\pi }{5}\] for some \[x\in (-1,\,1)\], then the value of \[{{\cos }^{-1}}x\] is  [IIT 1992]

    A) \[\frac{3\pi }{10}\]

    B) \[\frac{5\pi }{10}\]

    C) \[\frac{7\pi }{10}\]

    D) \[\frac{9\pi }{10}\]

    Correct Answer: A

    Solution :

      \[{{\sin }^{-1}}x+{{\cos }^{-1}}x=\frac{\pi }{2}\] Þ \[{{\cos }^{-1}}x=\frac{\pi }{2}-{{\sin }^{-1}}x=\frac{\pi }{2}-\frac{\pi }{5}=\frac{3\pi }{10}\] .


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