A) \[a+b=2|h|\]
B) \[a+b=-2h\]
C) \[a-b=2|h|\]
D) \[{{(a-b)}^{2}}=4{{h}^{2}}\]
Correct Answer: B
Solution :
Bisector of the angle between positive directions of the axes is\[y=x\]. Since it is one of the lines of the given pair \[a{{x}^{2}}+2hxy+b{{y}^{2}}=0,\] we have \[{{x}^{2}}(a+2h+b)=0\] or\[a+b=-2h\].
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