JEE Main & Advanced Chemistry Solutions / विलयन Question Bank Critical Thinking Solutions

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    A solution is obtained by dissolving 12 g of urea (mol.wt.60) in a litre of water. Another solution is obtained by dissolving 68.4 g of cane sugar (mol.wt. 342) in a litre of water at are the same temperature. The lowering of vapour pressure in the first solution is                                  [CPMT 2001]

    A)                 Same as that of 2nd solution

    B)                 Nearly one-fifth of the 2nd solution

    C)                 Double that of 2nd solution

    D)                 Nearly five times that of 2nd solution

    Correct Answer: A

    Solution :

             We know that in the first solution number of the moles of urea  \[=\frac{\text{Mass of urea}}{\text{ }m.wt.\text{ of urea}}\times \frac{1}{\text{V}}\]                             \[=\frac{12}{60}\times \frac{1}{1}=0.2\] and                                 In second solution the number of moles of cane sugar \[=\frac{\text{Mass of cane sugar}}{m.wt.\text{ of cane sugar}}\] \[=\frac{68.4}{342}\times \frac{1}{1}=0.2\].


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