A) \[12.2\,g\,mo{{l}^{-1}}\]
B) \[15.4\,g\,mol\]
C) \[17.3\,g\,mo{{l}^{-1}}\]
D) \[20.4\,g\,mol\]
Correct Answer: C
Solution :
First boiling point of water = \[{{100}^{o}}C\] Final boiling point of water = \[{{100.52}^{o}}\] \[w=3g\], \[W=200\,g\], \[{{K}_{b}}=0.6\,k{{g}^{-1}}\] \[\Delta {{T}_{b}}=100.52-100={{0.52}^{o}}C\] \[m=\frac{{{K}_{b}}\times w\times 1000}{\Delta {{T}_{b}}\times W}\]\[=\frac{0.6\times 3\times 1000}{0.52\times 200}=\frac{1800}{104}=17.3gmo{{l}^{-1}}\].
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