A) Cu with \[{{H}_{2}}S{{O}_{4}}\]
B) Sodium formate
C) Sodium oxalate
D) None of these
Correct Answer: B
Solution :
\[\underset{\text{Sod}\text{. formate}}{\mathop{2HCOONa}}\,(s)\xrightarrow{\Delta }{{H}_{2}}(g)\uparrow +\underset{\text{Sod}\text{. oxalate}}{\mathop{\underset{COONa}{\overset{COONa}{\mathop{|\ \ \ \ \ \ \ \ \ \ }}}\,}}\,(s)\]
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