A) 100 days
B) 10 days
C) 1 day
D) \[{{\log }_{e}}\]2 days
Correct Answer: B
Solution :
Quantity of radioactive element decayed\[=\frac{15}{16}\] Quantity left = \[1-\frac{15}{16}=\frac{1}{16}\] \[\frac{1}{16}=1\times {{\left( \frac{1}{2} \right)}^{n}}\]or \[{{\left( \frac{1}{2} \right)}^{4}}={{\left( \frac{1}{2} \right)}^{n}}\] one half-life = \[\frac{40}{4}=10\]days.
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